Optimal. Leaf size=149 \[ -\frac {\left (b^2 d-2 a c d-b c e\right ) \tanh ^{-1}\left (\frac {b+2 a x}{\sqrt {b^2-4 a c}}\right )}{a \sqrt {b^2-4 a c} \left (a d^2-e (b d-c e)\right )}+\frac {d^2 \log (d+e x)}{e \left (a d^2-b d e+c e^2\right )}-\frac {(b d-c e) \log \left (c+b x+a x^2\right )}{2 a \left (a d^2-e (b d-c e)\right )} \]
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Rubi [A]
time = 0.14, antiderivative size = 149, normalized size of antiderivative = 1.00, number of steps
used = 7, number of rules used = 6, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.273, Rules used = {1459, 1642,
648, 632, 212, 642} \begin {gather*} -\frac {\left (-2 a c d+b^2 d-b c e\right ) \tanh ^{-1}\left (\frac {2 a x+b}{\sqrt {b^2-4 a c}}\right )}{a \sqrt {b^2-4 a c} \left (a d^2-e (b d-c e)\right )}+\frac {d^2 \log (d+e x)}{e \left (a d^2-b d e+c e^2\right )}-\frac {(b d-c e) \log \left (a x^2+b x+c\right )}{2 a \left (a d^2-e (b d-c e)\right )} \end {gather*}
Antiderivative was successfully verified.
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Rule 212
Rule 632
Rule 642
Rule 648
Rule 1459
Rule 1642
Rubi steps
\begin {align*} \int \frac {1}{\left (a+\frac {c}{x^2}+\frac {b}{x}\right ) (d+e x)} \, dx &=\int \frac {x^2}{(d+e x) \left (c+b x+a x^2\right )} \, dx\\ &=\int \left (\frac {d^2}{\left (a d^2-e (b d-c e)\right ) (d+e x)}+\frac {-c d-(b d-c e) x}{\left (a d^2-e (b d-c e)\right ) \left (c+b x+a x^2\right )}\right ) \, dx\\ &=\frac {d^2 \log (d+e x)}{e \left (a d^2-b d e+c e^2\right )}+\frac {\int \frac {-c d-(b d-c e) x}{c+b x+a x^2} \, dx}{a d^2-e (b d-c e)}\\ &=\frac {d^2 \log (d+e x)}{e \left (a d^2-b d e+c e^2\right )}-\frac {(b d-c e) \int \frac {b+2 a x}{c+b x+a x^2} \, dx}{2 a \left (a d^2-e (b d-c e)\right )}+\frac {\left (b^2 d-2 a c d-b c e\right ) \int \frac {1}{c+b x+a x^2} \, dx}{2 a \left (a d^2-e (b d-c e)\right )}\\ &=\frac {d^2 \log (d+e x)}{e \left (a d^2-b d e+c e^2\right )}-\frac {(b d-c e) \log \left (c+b x+a x^2\right )}{2 a \left (a d^2-e (b d-c e)\right )}-\frac {\left (b^2 d-2 a c d-b c e\right ) \text {Subst}\left (\int \frac {1}{b^2-4 a c-x^2} \, dx,x,b+2 a x\right )}{a \left (a d^2-e (b d-c e)\right )}\\ &=-\frac {\left (b^2 d-2 a c d-b c e\right ) \tanh ^{-1}\left (\frac {b+2 a x}{\sqrt {b^2-4 a c}}\right )}{a \sqrt {b^2-4 a c} \left (a d^2-e (b d-c e)\right )}+\frac {d^2 \log (d+e x)}{e \left (a d^2-b d e+c e^2\right )}-\frac {(b d-c e) \log \left (c+b x+a x^2\right )}{2 a \left (a d^2-e (b d-c e)\right )}\\ \end {align*}
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Mathematica [A]
time = 0.09, size = 132, normalized size = 0.89 \begin {gather*} -\frac {2 e \left (-b^2 d+2 a c d+b c e\right ) \tan ^{-1}\left (\frac {b+2 a x}{\sqrt {-b^2+4 a c}}\right )+\sqrt {-b^2+4 a c} \left (-2 a d^2 \log (d+e x)+e (b d-c e) \log (c+x (b+a x))\right )}{2 a \sqrt {-b^2+4 a c} e \left (a d^2+e (-b d+c e)\right )} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.25, size = 130, normalized size = 0.87
method | result | size |
default | \(\frac {d^{2} \ln \left (e x +d \right )}{e \left (a \,d^{2}-d e b +c \,e^{2}\right )}+\frac {\frac {\left (-b d +c e \right ) \ln \left (a \,x^{2}+b x +c \right )}{2 a}+\frac {2 \left (-c d -\frac {\left (-b d +c e \right ) b}{2 a}\right ) \arctan \left (\frac {2 a x +b}{\sqrt {4 a c -b^{2}}}\right )}{\sqrt {4 a c -b^{2}}}}{a \,d^{2}-d e b +c \,e^{2}}\) | \(130\) |
risch | \(\frac {d^{2} \ln \left (e x +d \right )}{e \left (a \,d^{2}-d e b +c \,e^{2}\right )}+\left (\munderset {\textit {\_R} =\RootOf \left (\left (4 a^{3} c \,d^{2}-b^{2} d^{2} a^{2}-4 a^{2} b c d e +4 e^{2} c^{2} a^{2}+a \,b^{3} d e -a \,b^{2} c \,e^{2}\right ) \textit {\_Z}^{2}+\left (4 a b c d -4 a \,c^{2} e -b^{3} d +b^{2} c e \right ) \textit {\_Z} +c^{2}\right )}{\sum }\textit {\_R} \ln \left (\left (\left (-2 a^{3} d^{2} e +2 a^{2} b d \,e^{2}+6 e^{3} c \,a^{2}-2 a \,b^{2} e^{3}\right ) \textit {\_R}^{2}+\left (2 a^{2} d^{2}-a b d e -5 a c \,e^{2}+2 e^{2} b^{2}\right ) \textit {\_R} +b d +c e \right ) x +\left (-a^{2} b \,d^{2} e +8 a^{2} c d \,e^{2}-a \,b^{2} d \,e^{2}-a b c \,e^{3}\right ) \textit {\_R}^{2}+\left (d^{2} a b -5 a c d e +b^{2} d e +b c \,e^{2}\right ) \textit {\_R} +c d \right )\right )\) | \(291\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 1.17, size = 405, normalized size = 2.72 \begin {gather*} \left [\frac {2 \, {\left (a b^{2} - 4 \, a^{2} c\right )} d^{2} \log \left (x e + d\right ) + {\left (b c e^{2} - {\left (b^{2} - 2 \, a c\right )} d e\right )} \sqrt {b^{2} - 4 \, a c} \log \left (\frac {2 \, a^{2} x^{2} + 2 \, a b x + b^{2} - 2 \, a c + \sqrt {b^{2} - 4 \, a c} {\left (2 \, a x + b\right )}}{a x^{2} + b x + c}\right ) - {\left ({\left (b^{3} - 4 \, a b c\right )} d e - {\left (b^{2} c - 4 \, a c^{2}\right )} e^{2}\right )} \log \left (a x^{2} + b x + c\right )}{2 \, {\left ({\left (a^{2} b^{2} - 4 \, a^{3} c\right )} d^{2} e - {\left (a b^{3} - 4 \, a^{2} b c\right )} d e^{2} + {\left (a b^{2} c - 4 \, a^{2} c^{2}\right )} e^{3}\right )}}, \frac {2 \, {\left (a b^{2} - 4 \, a^{2} c\right )} d^{2} \log \left (x e + d\right ) + 2 \, {\left (b c e^{2} - {\left (b^{2} - 2 \, a c\right )} d e\right )} \sqrt {-b^{2} + 4 \, a c} \arctan \left (-\frac {\sqrt {-b^{2} + 4 \, a c} {\left (2 \, a x + b\right )}}{b^{2} - 4 \, a c}\right ) - {\left ({\left (b^{3} - 4 \, a b c\right )} d e - {\left (b^{2} c - 4 \, a c^{2}\right )} e^{2}\right )} \log \left (a x^{2} + b x + c\right )}{2 \, {\left ({\left (a^{2} b^{2} - 4 \, a^{3} c\right )} d^{2} e - {\left (a b^{3} - 4 \, a^{2} b c\right )} d e^{2} + {\left (a b^{2} c - 4 \, a^{2} c^{2}\right )} e^{3}\right )}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 3.32, size = 149, normalized size = 1.00 \begin {gather*} \frac {d^{2} \log \left ({\left | x e + d \right |}\right )}{a d^{2} e - b d e^{2} + c e^{3}} - \frac {{\left (b d - c e\right )} \log \left (a x^{2} + b x + c\right )}{2 \, {\left (a^{2} d^{2} - a b d e + a c e^{2}\right )}} + \frac {{\left (b^{2} d - 2 \, a c d - b c e\right )} \arctan \left (\frac {2 \, a x + b}{\sqrt {-b^{2} + 4 \, a c}}\right )}{{\left (a^{2} d^{2} - a b d e + a c e^{2}\right )} \sqrt {-b^{2} + 4 \, a c}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 3.67, size = 966, normalized size = 6.48 \begin {gather*} \frac {d^2\,\ln \left (d+e\,x\right )}{a\,d^2\,e-b\,d\,e^2+c\,e^3}-\frac {\ln \left (a\,b^2\,d^4-2\,c^3\,e^4-4\,a^2\,c\,d^4+b^3\,d^3\,e+c^2\,e^4\,x\,\sqrt {b^2-4\,a\,c}+10\,a\,c^2\,d^2\,e^2-4\,b^2\,c\,d^2\,e^2-b^3\,d^2\,e^2\,x+a\,b\,d^4\,\sqrt {b^2-4\,a\,c}+3\,b\,c^2\,d\,e^3-b\,c^2\,e^4\,x+b^2\,d^3\,e\,\sqrt {b^2-4\,a\,c}+3\,c^2\,d\,e^3\,\sqrt {b^2-4\,a\,c}+2\,a^2\,d^4\,x\,\sqrt {b^2-4\,a\,c}+3\,a\,b^2\,d^3\,e\,x+6\,a\,c^2\,d\,e^3\,x-10\,a^2\,c\,d^3\,e\,x-2\,b\,c\,d^2\,e^2\,\sqrt {b^2-4\,a\,c}-3\,a\,b\,c\,d^3\,e+b^2\,d^2\,e^2\,x\,\sqrt {b^2-4\,a\,c}-5\,a\,c\,d^3\,e\,\sqrt {b^2-4\,a\,c}-a\,b\,d^3\,e\,x\,\sqrt {b^2-4\,a\,c}+a\,b\,c\,d^2\,e^2\,x-5\,a\,c\,d^2\,e^2\,x\,\sqrt {b^2-4\,a\,c}\right )\,\left (e\,\left (\frac {b^2\,c}{2}-2\,a\,c^2+\frac {b\,c\,\sqrt {b^2-4\,a\,c}}{2}\right )-\frac {b^3\,d}{2}-\frac {b^2\,d\,\sqrt {b^2-4\,a\,c}}{2}+a\,c\,d\,\sqrt {b^2-4\,a\,c}+2\,a\,b\,c\,d\right )}{4\,a^3\,c\,d^2-a^2\,b^2\,d^2-4\,a^2\,b\,c\,d\,e+4\,a^2\,c^2\,e^2+a\,b^3\,d\,e-a\,b^2\,c\,e^2}+\frac {\ln \left (2\,c^3\,e^4-a\,b^2\,d^4+4\,a^2\,c\,d^4-b^3\,d^3\,e+c^2\,e^4\,x\,\sqrt {b^2-4\,a\,c}-10\,a\,c^2\,d^2\,e^2+4\,b^2\,c\,d^2\,e^2+b^3\,d^2\,e^2\,x+a\,b\,d^4\,\sqrt {b^2-4\,a\,c}-3\,b\,c^2\,d\,e^3+b\,c^2\,e^4\,x+b^2\,d^3\,e\,\sqrt {b^2-4\,a\,c}+3\,c^2\,d\,e^3\,\sqrt {b^2-4\,a\,c}+2\,a^2\,d^4\,x\,\sqrt {b^2-4\,a\,c}-3\,a\,b^2\,d^3\,e\,x-6\,a\,c^2\,d\,e^3\,x+10\,a^2\,c\,d^3\,e\,x-2\,b\,c\,d^2\,e^2\,\sqrt {b^2-4\,a\,c}+3\,a\,b\,c\,d^3\,e+b^2\,d^2\,e^2\,x\,\sqrt {b^2-4\,a\,c}-5\,a\,c\,d^3\,e\,\sqrt {b^2-4\,a\,c}-a\,b\,d^3\,e\,x\,\sqrt {b^2-4\,a\,c}-a\,b\,c\,d^2\,e^2\,x-5\,a\,c\,d^2\,e^2\,x\,\sqrt {b^2-4\,a\,c}\right )\,\left (\frac {b^3\,d}{2}+e\,\left (2\,a\,c^2-\frac {b^2\,c}{2}+\frac {b\,c\,\sqrt {b^2-4\,a\,c}}{2}\right )-\frac {b^2\,d\,\sqrt {b^2-4\,a\,c}}{2}+a\,c\,d\,\sqrt {b^2-4\,a\,c}-2\,a\,b\,c\,d\right )}{4\,a^3\,c\,d^2-a^2\,b^2\,d^2-4\,a^2\,b\,c\,d\,e+4\,a^2\,c^2\,e^2+a\,b^3\,d\,e-a\,b^2\,c\,e^2} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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